-2x^2+402x-4180=0

Solution for -2x^2+402x-4180=0 equation:

-2x^2+402x-4180=0

a = -2; b = 402; c = -4180;
Δ = b2-4ac
Δ = 4022-4·(-2)·(-4180)
Δ = 128164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{128164}=358$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(402)-358}{2*-2}=\frac{-760}{-4}
=+190
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(402)+358}{2*-2}=\frac{-44}{-4}
=+11
$